Joe is performing a dilation. One of his points is Y'(-4, 2), and another point is Y(-2, 1). What scale factor is he using?

Begin by clearly stating the problem; you can copy this from the problem set file. Show how you solved the problem step by step,

iogann1982 [59]

Answer: 13%

Step-by-step explanation:

We know that the formula to find the simple interest :

$I=Prt$ , where P is the principal amount , r is rate (in decimal )and t is the time period (in years).

Given : Albert borrowed $19,100 for 4 years. The simple interest is $9932.00. Find the rate.

i.e. P = $19,100 and t= 4 years and I = $9932.00

Now, Substitute all the values in the formula , we get

$9932=(19100)r(4)\\\\\Rightarrow\ r=\dfrac{9932}{19100\times4}\\\\\Rightarrow\ r=0.13\ \ \ \text{[On simplifying]}$

In percent, $r=0.13\times100\%=13\%$

Hence, the rate of interest = 13%

3 0

2 years ago

A test has 20 true/false questions. What is the probability that a student passes the test if they guess the answers? Passing me

Minchanka [31]

Using the binomial distribution, it is found that:

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

For each question, there are only two possible outcomes, either the guess is correct, or it is not. The guess on a question is independent of any other question, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 20 questions, hence $n = 20$ .

Each question has 2 options, one of which is correct, hence $p = \frac{1}{2} = 0.5$

The probability is:

$P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148$

$P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046$

$P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011$

$P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002$

$P(X = 16) = C_{20,19}.(0.5)^{19}.(0.5)^{1} = 0$

$P(X = 17) = C_{20,20}.(0.5)^{20}.(0.5)^{0} = 0$

Then:

$P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0207$

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

You can learn more about the binomial distribution at brainly.com/question/24863377

6 0

2 years ago

US Department of Transportation As part of a study on transportation safety, the US Department of Transportation collected data

Nonamiya [84]

Answer:

we can conclude that for every single unit of : x, y would be increased by 0.2871. and intersection of x and y will be through =1.5974

it can be concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21

Step-by-step explanation:

WITH THE GIVEN DATA

A ) using regression to investigate the relationship between the number of fatal accidents and the percentage of drivers under the age pf 21

to fit into a regression line we must have ∝ and β

where β = $\frac{S_{xy} }{S_{xx} }$ = 0.2871

and ∝ = y - βx = - 1.5974

regression line = ∝ + β * x

insert values into regression line equation

regression line = -1.5974 + 0.2871 * x

we can conclude that for every single unit of : x, y would be increased by 0.2871. and intersection of x and y will be through =1.5974

B ) conclusion and recommendations can you derive from your analysis

it can be concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21

using the correlation coefficient ( r ) = $\frac{S_{xy} }{\sqrt{S_{xx}*S_{xy} } }$ = 0.8394

5 0

2 years ago

Steve is three more than 5 times as old as his cousin. If the sum of their ages is 21, how old is Kia's cousin? Solve and write

DerKrebs [107]

Answer:

34

Step-by-step explanation:

Cause it is right

8 0

2 years ago

What is the coefficient of x5y5 in the expansion of (x + y)10?

butalik [34]

Answer:

C=252

Step-by-step explanation:

Given:

x^5y^5

(x+y)^10

Find the coefficient of x^5y^5

To get the coefficient of x^5y^5,

we will put r = 5, in the below given general term.

The general term is : nCr =x^ry^n-r

We get:

Coefficient is = 10C5

= 10!/5!*5!

= 252

The coefficient of x^5y^5 is 252

C. 252

4 0

2 years ago

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