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2 years ago

Which associations best describe the scatter plot?

Mathematics

2 answers:

LenKa [72]2 years ago

4 0

Answer: Here you go hope this helps

If a line is drawn through (twenty, seventy) and (twenty-five, sixty), then you can use the points in getting the equation.

Slope is = (60-70)/(25-20) = -2

Using the two-point slope form, y – y1 = m(x – x1)

y – 70 = -2(x – 20)

y – 70 = -2x + 40

y = -2x + 110

Step-by-step explanation:

slamgirl [31]2 years ago

4 0

Answer:

negative and nonlinear

Step-by-step explanation:

took the k12 test

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The first 6 nonzero multiples of 5

Vikentia [17]

5 0

3 years ago

Pls help with mathh!!!

sergeinik [125]

Answer: x<5

Step-by-step explanation:

If the circle was dark then it would be x is less than or equal to 5. But here, since the circle is open, that means that 5 is not a possible solution for x. The answer is x<5. Hope this helps!

6 0

3 years ago

A lab is testing the amount of a certain active chemical compound in a particular drug that has been recently developed. The man

Mazyrski [523]

Answer:

The 95% confidence interval is "87.94, 91.86".

Step-by-step explanation:

The given values are:

Sample batches,

n = 25

Sample mean concentration,

$\bar{x}$ = 89.9 mg

Amount of chemical,

σ = 5

α = 0.05

The critical value from Z table will be:

= $Z(\frac{\alpha}{2} )$

= $Z(\frac{0.05}{2} )$

= $1.96$

Now,

The confidence interval will be:

= $\bar{x} \pm Z(\frac{\alpha}{2} )\times \frac{\sigma}{\sqrt{n} }$

On substituting the values, we get

= $89.9 \pm Z(\frac{0.05}{2})\times \frac{5}{\sqrt{25}}$

= $89.9 \pm Z(\frac{0.05}{2})\times \frac{5}{5}$

= $89.9 \pm1.96\times 1$

Lower limit will be:

= $89.9 -1.96\times 1$

= $87.94$

Upper limit will be:

= $89.9 +1.96\times 1$

= $91.86$

7 0

2 years ago

How many cubes with an edge length of 1/3 inches does it take to fill a box with width 2 and 2/3 inches, length 3 and 1/3 inches

KatRina [158]

Answer:

Step-by-step explanation:

6 0

2 years ago

Factor & Finding Zeros<br> x^{2} -x-6=0

Mamont248 [21]

Answer:

x = 3, -2

Step-by-step explanation:

To help us factor, we can split the middle term up into the sum of the terms -3x and 2x:

$x^2+(-3x)+2x-6=0$

From there, we can factor out an x from the first two term and a 2 from the last two to obtain the equation

$x(x-3)+2(x-3)=0$

Factoring out an (x - 3) from each term gives us the equation

$(x-3)(x+2)=0$

At this point, we can divide by either x - 3 or x + 2 to obtain the two equations

$x-3=0$ and $x+2=0$

Solving both for x gives us the solutions x = 3 and x = -2. We can verify these by substituting them back into the original equation:

$3^2-3-6=0\\9-3-6=0\\6-6=0\\0=0$

$(-2)^2-(-2)-6 = 0\\4+2-6=0\\6-6=0\\0=0$

3 0

3 years ago