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Misha Larkins [42]
3 years ago
10

What is the lateral surface area of the square pyramid represented by this net?

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

If you know the answer to this just put it down below

Step-by-step explanation:

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A popular online music store allowed shoppers to listen to an entire album before buying it. Of the people who listened to the w
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Answer:

IDK this stuff is confusing

Step-by-step explanation:

Plz like and follow

4 0
3 years ago
Write the following as an inequality
Ipatiy [6.2K]

Answer:

3 ≤ w ≤ 4

Step-by-step explanation:

the statements are 3 ≤ w  and 4 ≥ w ( or w ≤ 4 )

These can be combined into the single inequality

3 ≤ w ≤ 4


4 0
3 years ago
Choose the correct proportions.
cestrela7 [59]

Answer:

Options A, B and C are CORRECT PROPORTIONS

Step-by-step explanation:

Option A

3:5 = 6:10

The LHS must equal the RHS

3:5 is in it's lowest term.

6/10 will be in it's lowest term by dividing the numerator and denominator by 2.

6/10 = 3/5

Option B

3/6 and 5/10.

Diving 3/6 fractions by 3

= 1/2

Dividing 5/10 fraction by 5

= 1/2

Option C

Dividing 6/3 by 3 = 2

Dividing 10/5 by 5 = 2

Thats how you work through equivalent proportional fractions

6 0
3 years ago
What fractions are the common denominators for 1/2 and 7/8
Orlov [11]

Answer:

lowest:8 more:16 32 64

Step-by-step explanation:

3 0
2 years ago
Tameka built 1/2 of a shed on Monday and 2/5 of the shed on Tuesday. Tameka finished building the shed of Wednesday. What fracti
Doss [256]

Step One

Find the sum of the fractions for Monday and Tuesday

1/2 + 2/5

The common denominator for these 2 days is 10

1/2: 1*5/(2*5) = 5/10

2/5:2*2/(2*5) = 4/10

Add these two equivalent fractions together.

5/10 + 4/10 = 9/10

The first 2 days resulted in 9/10 of the shed being completed.

Step Two

Find out how much (in terms of fractions) is left of the shed.

Let the whole shed = 1

Let what has been done = 9/10

What remains is 1 - 9/10 = 1/10

Answer: 1/10 of the shed needs to be done

4 0
3 years ago
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