To help you out I save your picture and explain the process. The only thing tht confuses me is problem #!6. But I hope I helped you out in the slightest bit
To solve this we are going to use the half life equation

Where:

is the initial sample

is the time in years

is the half life of the substance

is the remainder quantity after

years
From the problem we know that:



Lets replace those values in our equation to find

:




We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be
91.7 grams.
I am gonna assume it is C)9/4 - 1/2i
Answer:
47.4167
D. The computed mean is close to the actual mean because the difference between the means is less than 5%
Step-by-step explanation:
Given the distribution :
Speed(m/hr) ___ midpoint(x) ___ F ___fx
42 - 45 _______ 43.5 ________21 __ 913.5
46 - 49 _______47.5 _________15 __712.5
50 - 53 _______ 51.5 _________6 __ 309
54 - 57 _______ 55.5 ________ 4 ___ 222
58 - 61 ________59.5 ________ 2 ___ 119
The midpoint, x= sum of lower and upper boundary divided by 2
For instance, (42 + 45) / 2 = 43.5
The computed mean, Σfx / Σf = 2276 / 48 = 47.4167
Actual mean = 47.3 miles
(47.4167 - 47.3) / 47.3 * 100% = 0.24%
Answer:
b (2,2)
Step-by-step explanation: