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Schach [20]
3 years ago
13

If the pattern below follows the rule "Starting with five, every consecutive line has a number one more than the previous line,"

how many marbles must be in the seventh line?

Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer: 11

Step-by-step explanation: all you have to do is start from add 1 each time you add a new line. You could do this using your fingers. Raise a finger for each line and count. Start at 5 for your first finger, and continue adding 1. Once you reach 7 fingers, you’ll have reached the number 11. This is the amount of marbles you have. You could also simply do 6+5, because you are adding 6 lines so you’ll have 6 more marbles then in the first line.

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Now, the probability that eight receipts will show that the above three food items were ordered :

P(X=8)=\ ^{10}C_8(0.32)^8(1-0.32)^2\\\\=\dfrac{10!}{8!2!}(0.32)^8(0.68)^2\\\\=5\times9(0.0000508414176684)\\\\=0.00228786379508\approx0.0023

hence, the required probability = 0.0023

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