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Troyanec [42]
3 years ago
8

what statement is false. A. Every rational number is also real B. Every real number is also rational C. Every integer is also a

rational number D. No ration number is an integer
Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0
Wrong is <span>B. Every real number is also rational </span>
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What is the difference between a triangular number and a cube number?
pav-90 [236]
A cube number is an integer which is a third power of another integer.

A triangular number is a number that counts the objects that can form equilateral triangle (sorry, I cribbed it a little from Wikipedia; it's difficult to explain). Just look at the picture.
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8 0
2 years ago
Wich is the result of 23*1/5?
aleksklad [387]

Answer:

The answer is \frac{23}{5} or 4.6 .

Step-by-step explanation:

Solve the following equation:

23 \times \frac{1}{5}

-Multiply 23 and \frac{1}{5} to get

23 \times \frac{1}{5} = \frac{23}{5} = 4.6

So, now you have found the answer.

8 0
2 years ago
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A jewelry store is selling a set of 4 pairs of gemstone earrings for $58, including tax. Neva and three of her friends want to b
Marat540 [252]


Each member should pay $14.5, including tax.
4 0
3 years ago
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Convert 2/50 to percent
vodomira [7]

Answer: 4%

Step-by-step explanation: 50 x 2 = 100

2x2=4 4/100 or 4%

8 0
3 years ago
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If 32 teams participate in a standard single elimination tournament, how many games must be played to decide a champion?
SCORPION-xisa [38]
<h3>Answer: 31 games</h3>

======================================================

Explanation:

  • 32/2 = 16 games will happen in round 1. Afterward, 16 teams are left.
  • 16/2 = 8 games will happen in round 2. Afterward, 8 teams are left.
  • 8/2 = 4 games happen in round 3.
  • 4/2 = 2 games in round 4.
  • 2/2 = 1 game as the final championship.

Count the number of times you divide by two and we have five occurrences of this. So there five rounds overall.

To get the total number of games played, we add up the quotients

16+8+4+2+1 = 31

----------------

Or as a shortcut we can simply subtract off 1 since 1+2+4+...+2^n = 2^(n+1)-1

We can write that rule as

\displaystyle \sum_{k=1}^{n}2^k = 2^{n+1}-1

which is equivalent to

\displaystyle \sum_{k=1}^{n}2^{k-1} = 2^n-1

3 0
3 years ago
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