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2 years ago

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An appliance store sells a washer-dryer combination for $2650. If the washer cost $425 more than the dryer, find the cost of eac

h appliance

2 answers:

Yuri [45]2 years ago

5 0

Answer:

dryer= 1112.5

washer= 1537.5

Step-by-step explanation:

so we will use algebra to solve this by equating the dryer to "x" and washer to "x + 425"

dryer = x

washer = x + x + 425 = 2650

we collect the like terms by adding x + x

2x + 425 = 2650

the 425 crosses the equal sign hence becoming minus

2x = 2650 - 425

2x = 2225

x=2225/2

x = 1112.5

if you rember we uquated the ddyer to x meaning the dryer = 1112.5

meaning the washer = 1112.5 + 425 because of (x + 425) = 1537.5

skad [1K]2 years ago

4 0

Make an equation:

x + x + 425 = 2650

Isolate the variable:

2x = 2225

x = 1112.5

Now that we know what X is, we know that X + 425 will equal the cost of the second appliance

1112.50 + 425.00

= 1,537.50

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

Here is the complete question:

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3 years ago

Bob believes his test grade varies directly with the number of hours he spends studying and inversely with the number of hours h

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Answer: Hello mate!

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An inverse variation has the form y = k/x where also k is a real number.

them, if we define s as the hours that Bob spends studying, and b as the hours that he spends playing baseball, then the equation that represents the score is:

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3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

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Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

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We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

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The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

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$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

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$F=\frac{s_B^2}{s_W^2}$

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= 3.036212

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The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

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Step-by-step explanation:

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