Y<3x+4 in graph help me please!!!!
1 answer:
Graph the boundary line of y = 3x + 4 first. This is pretty easy. I'll give the steps below.
1. plot the y intercept: we see from the equation, the y intercept is 4 or specifically the point (0,4).... plot this as your first point.
2. Use the slope to get another point or couple of points. We can see from the equation that the slope is 3(the coefficient of 'x') and can be represented as a fraction
This fraction implies that you would move up three units of space and to the right 1 unit of space from the y intercept to get to your next point.
3. Draw a broken or dashed line through these two points due to the type of inequality symbol you have in the original problem(a less than symbol). This means the points that lie on this line will not actually by solutions.
4. Now that you have the boundary line sketched, all the points falling below the boundary line will be the solutions to the inequality <span>Y<3x+4 So shade that region of your graph.
5. To prove this, you can test the point (0,0) as follows: 0</span><span><3(0)+4
or, 0</span><4 which is a true statement, meaning the point (0,0) is a solution as well as all other points on that side of the boundary line.
Good luck ,, and I hope this helped.
1. plot the y intercept: we see from the equation, the y intercept is 4 or specifically the point (0,4).... plot this as your first point.
2. Use the slope to get another point or couple of points. We can see from the equation that the slope is 3(the coefficient of 'x') and can be represented as a fraction
3. Draw a broken or dashed line through these two points due to the type of inequality symbol you have in the original problem(a less than symbol). This means the points that lie on this line will not actually by solutions.
4. Now that you have the boundary line sketched, all the points falling below the boundary line will be the solutions to the inequality <span>Y<3x+4 So shade that region of your graph.
5. To prove this, you can test the point (0,0) as follows: 0</span><span><3(0)+4
or, 0</span><4 which is a true statement, meaning the point (0,0) is a solution as well as all other points on that side of the boundary line.
Good luck ,, and I hope this helped.
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Answer:
Second : 1/6 x + 47
Third : 1 2/3 x + 35 - 1 1/2 x + 12
Fourth : 5 (1/3x) + (5) (7) - (3) (1/2x) + (3) (4)
Step-by-step explanation:
I would start by expanding the expression, showing each step. Then, simplify by collecting like terms.
To expand, you multiply the term outside of the brackets by each term inside the brackets.
5(1/3x + 7) - 3(1/2x - 4)
= 5(1/3x) + (5)(7) - (3)(1/2x) + (3)(4) Showing how to expand
= 5/3x + 35 - 3/2x + 12 Simplified above step by multiplying
= 5/3x - 3/2x + 47 Collected like terms (35 + 12 = 47)
= 10/6x - 9/6x + 47 Change fractions to the common denominator 6
= + 47 Combine fractions with common denominator
= 1/6x + 47 Fully expanded
See which options match the steps I took to expand the original expression.
The second step is the same as option 4.
The last step is the same as option 2.
I bolded those steps that are the same.
Some options use mixed fractions (whole numbers and fractions).
From the third step, I will convert the improper fractions to mixed fractions.
5/3x + 35 - 3/2x + 12
= 1 2/3x + 35 - 1 1/2x + 12
This is the same as option 3.
On the left side, 5 goes into 3 ONE time. The ONE becomes the whole number. After 5 goes into 3, there is 2 left, which becomes the numerator.
On the left side, 3 goes into 2 ONE time. The ONE becomes the whole number. The remainder is 1, which becomes the numerator.