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finlep [7]
2 years ago
8

How many solutions exist for the given equation?

Mathematics
1 answer:
andrey2020 [161]2 years ago
3 0

Answer:

1

Step-by-step explanation:

as the maximum degree is 1

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-8-8x^2=-31<br> how to solve for x
Zepler [3.9K]

Answer:

x = ± \sqrt{\frac{23}{2\sqrt{2}}}

Step-by-step explanation:

-8 - 8x^2= -31

Since this is a quadratic, it needs to be factored.

First, move the x to the other side:

-8 = 8x^2 - 31

Then, get the x alone by first adding 31:

23 = 8x^2

then dividing by 8:

x^2 = 23/8

Finally, square root both sides and remember the even roots property:

x = ± \sqrt{\frac{23}{8}}

and simplify the root 8:

x = ±  \sqrt{\frac{23}{2\sqrt{2}}}

Note: This answer may have a mistake.

8 0
2 years ago
Can someone help me with this problem too?
marusya05 [52]
X equals 8 bu i dont know the slope
6 0
3 years ago
A contractor purchases a shipment of 100 transistors. It is his policy to test 10 of these transistors and to keep the shipment
Serjik [45]

Answer:

Hence the probability of the at least 9 of 10 in working condition is 0.3630492

Step-by-step explanation:

Given:

total transistors=100

defective=20

To Find:

P(X≥9)=P(X=9)+P(X=10)

Solution:

There  are 20 defective and 80 working transistors.

Probability of at least 9 of 10 should be working out 80 working transistors

is given by,

P(X≥9)=P(X=9)+P(X=10)

<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>

P(X≥9)={80C9*20C(10-9)}/(100C10)+{80C10*20(10-10)}/(100C10)

<em>(Use the permutation and combination calculator)</em>

P(X≥9)=(231900297200*20/17310309456440)

+(1646492110120/17310309456440)

P(X≥9)=0.267933+0.0951162

P(X≥9)=0.3630492

4 0
3 years ago
Find the absolute value of 4k-4.
lukranit [14]
It might be k, since 4-4 is 0 and 0 has no absolute value.
4 0
3 years ago
(-5) -2-8 + 1<br>1-5-2-8<br>helpp plisssssss ​
Hoochie [10]

Answer:

-14

Step-by-step explanation:

(-5)-2-8+1

-5-2-8+1

-7-8+1

-15+1

-14

5 0
3 years ago
Read 2 more answers
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