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luda_lava [24]
3 years ago
13

A movie is 2 hours and 28 minutes long it starts at 7:20pm at what time will the movie end

Mathematics
2 answers:
umka2103 [35]3 years ago
6 0
Movie starts 7:20 PM
2 hours = 02:00
28 minutes = 00:28

1.) 2 hours and 28 minutes = 02:28
2.) Movie starts 7:20 PM

You want to find out what time the movie will end

      07:20 PM (start time)
   + 02:28       (movie time)
-------------------------------------
      09:48 PM (movie end)

The movie will end at 9:48 PM
Lerok [7]3 years ago
6 0
First, we add two hours to 7:20, making it 9:20.  Then we add 28 minutes to 9:20 and we get a final answer of 9:48.

Hope this helped.
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ANTONII [103]
Megan:
x to the one third power =  x ^{1/3}
<span>x to the one twelfth power = </span>x ^{1/12}

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>\frac{x ^{1/3}}{x ^{1/12}}
<span>
Since </span>\frac{ x^{a} }{ x^{b} } = x ^{a-b}
then \frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}


Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>\sqrt[32]{x* x^{2} * x^{5} }
<span>
Since </span>x^{a}* x^{b}= x^{a+b}
Then \sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }

Since \sqrt[n]{x^{m}} = x^{m/n} }
Then \sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
3 0
3 years ago
Suppose we want to choose 5 objects, without replacement, from 9 distinct objects. (a) How many ways can this be done, if the or
7nadin3 [17]

Answer:

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if order matters...

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3 0
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