Answer:
Step-by-step explanation:
For this case we can define the random variable of interest as: "The nicotine content in a single cigarette " and for this case we know the following parameters:

And for this case we select a sample size of n =100 and we want to find the following probability:

And for this case we can use the z score formula given by:

And replacing we got:

And we can find the required probability with the normal standard table and we got:

Answer:
Step-by-step explanation:
The answer is 33
3(-2)^2+4(-2)+5
-6^2+ (-8) + 5
36 + (-8) + 5
28+5
33
3²×2^4 ×3³×2=
3^5×2^5=
243 × 32 = 7776