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const2013 [10]
3 years ago
11

28 x 9 x 3 - 1 = ? HELP PLS

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0
The correct answer is 755
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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. The simplest form o
sleet_krkn [62]

Answer:

x

Step-by-step explanation:

-2x²(x – 5) + x(2x² – 10x) + x

The simplest for of the above equation can be obtained as follow:

-2x²(x – 5) + x(2x² – 10x) + x

Rearrange

x(2x² – 10x) – 2x²(x – 5) + x

Factorise

x.2x(x – 5) – 2x²(x – 5) + x

2x²(x – 5) – 2x²(x – 5) + x

Carry out the minus (–) operation

=> x

Therefore, the simplest form of expressing -2x2(x – 5) + x(2x2 – 10x) + x is x.

6 0
4 years ago
Boat A traveled at a speed of 15km/h for 7h a day. Boat B traveled at a speed of 25km/h for 6h a day. Find the difference travel
-BARSIC- [3]

Answer:

Boat A travels 105 km

Boat B travels 150 km

difference 45 km

8 0
3 years ago
Mr. Peter's has 80 sheets of colored paper. Seven of his students need the paper for a project. How many sheets does each studen
Julli [10]

Answer:

Each student gets 11 pieces.

Step-by-step explanation:

80 ÷ 7 = 11.42857

80 divided by 7 comes out to a decimal therefore, you will have a remainder. 7 × 11 = 77

The answer would be 11 remainder 3.

8 0
3 years ago
Explain the difference between dry friction and drag due to fluid friction
lukranit [14]

Answer: Fluid friction describes the friction between layers of a viscous fluid that are moving relative to each other

Hope it helps:) I got it right on my test btw

Step-by-step explanation:

3 0
4 years ago
yuri has a rope 12 meters long. he cuts it into pieces that are each 2 meters long. what fraction of the rope is one piece
Lelu [443]
So the numerator of your fraction (the top number) is the amount that was cut. The denominator (the bottom number) is the total amount of rope. So, your fraction would be 2/12. You can still simplify that by dividing both the numerator and denominator by 2 and end up with 1/6. Does that make sense? If you need any more help, go ahead and message me :)
6 0
3 years ago
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