What is the answer? Please tell me soon.

Hey yo can somebody help me tell me the anwser thank you

Veseljchak [2.6K]

Answer should be A.
GJ/MN = 7/4

hope it helps

7 0

4 years ago

Write the equation below in slope intercept form. x + 2y = 4

Anestetic [448]

Answer:

y = − 1 /2 x + 2 is slope

Step-by-step explanation:

Hope this helps.

3 0

3 years ago

Read 2 more answers

If the percent transmittance for a sample is 50 at 350 nm what is the value of a

LenaWriter [7]

Answer: The value of absorbance is 0.3010

Step-by-step explanation:

Transmittance,(T)= 50%

Absorbance, (A)= ?

$A=-\log(\frac{T\%}{100})$

Transmittance and absorbance are inversely related:

$A=-\log\frac{50}{100}=0.3010$

Hence,the value of absorbance is 0.3010 when transmittance was 50%.

6 0

4 years ago

Read 2 more answers

Find the number of faces, edges, and vertices of the solid. Please help me with this problem!

sp2606 [1]

Answer:

Faces: 7, Edges: 12, Vertices: 7

Step-by-step explanation:

Just count them

7 0

3 years ago

If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:

Liula [17]

Answer:

(a) The mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of X are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable X follows a Binomial distribution with parameters n and p.

The mean, variance and standard deviation of X are:

$\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}$

(a)

For n = 4 and p = 0.40 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98$

Thus, the mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b)

For n = 4 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80$

Thus, the mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(c)

For n = 3 and p = 0.50 compute the mean, variance and standard deviation of X as follows:

$\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87$

Thus, the mean, variance and standard deviation of X are 1.50, 0.75 and 0.87 respectively.

(d)

For n = 5 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89$

Thus, the mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

6 0

3 years ago