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nikdorinn [45]
3 years ago
8

Graph the equation y=x²-8x+7 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

vertex is: (4,-9)

y intercept= (0,7)

roots= (1,0) and (7,0)

Step-by-step explanation:

so we can use factoring to solve this quadratic equation real quick:

x^2-7x-1x+7

x(x-7)

-1(x-7)

(x-1)(x-7)=0

x-1=0

x=1

x-7=0

x=7

(1,0) and (7,0) are the roots

axis of symmetry: 8/2=4

substitute axsis of symmetry in equation to get vertex:

4^2-8(4)+7

16-32+7

-16+7=-9

vertex is: (4,-9)

y intercept= (0,7)

roots= (1,0) and (7,0)

Hope this helps

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What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
3 years ago
Which tiles should be added to the model below to make zero?​
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Solve the equation using the order of operations.<br><br> 5+{2×[(5−1)+6]}÷4
creativ13 [48]

Answer:

The order of operations is PEMDAS

First step is to do everything is parenthesis or brackets

5+{2*[(5-1)+6]}/4

{2*[(5-1)+6]}

First you would go 5-1=4, because that is the first equation that is in parenthesis by itself.

{2*[4+6]}

Next you would go 4+6=10, because that is your next smallest bracket

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Last you would go 2*10=20

Your equation now looks like this

5+{20}/4

In PEMDAS your next step is exponents, but we don't have any so we go on to the next one which is multiply/division

5+5

You would go 20/4=5

Last step is to add/subtract

5+5=10

Your final answer would be 10

Hope this helps ;)

Step-by-step explanation:

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babunello [35]

Answer: -40 or negative forty

Step-by-step explanation:

6 0
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