Answer:
Step-by-step explanation:
If x is the white dot on the graph:
From what it looks like, x is right between -35 and -34 x (which is -35.5).
If that is the case then none of the answers are correct since -35.5 is <u>equal or less</u> than x. (the sign looks like this: "
" )
But if you have to choose one of the answers then number 4 (-35.5 < x) would be closest.
The solution (x,y) needs to work in both equations. With multiple choice you can do guess and test method. Otherwise you need to combine the two equations into one by substitution or elimination methods.
21. substitution works well here since one equation is y= x+3. you can easily substitute the (x+3) for y in the other equation.
2x + (x+3) = -6
3x + 3 = -6
3x = -9
x = -3
use this in either equation to find y.
y = (-3)+3
solution: (-3,0)
22. these both equal y so they equal each other.
4x - 1 = 3x +6
4x - 3x = 6 + 1
x = 7
use this in either equation to find y
y = 4(7) - 1
y = 28 - 1
y = 27
solution: (7,27)
23. one equation is y = 2x - 3. So substitute (2x -3) for y in the other equation.
4x = 2(2x - 3) + 6
4x = 4x - 6 + 6
4x = 4x
x = x
any solution will work, infinitely many.
24. infinitely many solutions means the two equations are the same equation. Like the previous one they didn't look the same but if you put them both in terms of y...
y= 2x-3
4x = 2y + 6
4x - 6 = 2y
(4x - 6)/2 = y
2x - 3 = y
same equation.
from the image, I can't see all options but A & C do not look like the same equations. It's got to be either B or D.
Answer:
No.
Step-by-step explanation:
No because if we substitute the given values into the equation they do not fit:
y = 7x
x = 1 and y = 4:
Left side = 4
right side = 7*1 = 7.
8, 7, undefined, 6*sqrt *2
Answer:
brownies per hour
Step-by-step explanation:
Given parameters:
Number of brownies = 
of a dozen
Time taken = 3hrs
Unknown:
Average baking per hour = ?
Solution:
The average baking per hour;
This is a rate problem;
Average baking per hour = 
Number of brownies = x 12 = 
Average baking per hour = 
= 
= 
= 3
brownies per hour
