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4 years ago

Why is it important to have a control group in an experimental investigation?

2 answers:

8 0

a control group provides a baseline for the experiment, shows how the independent variable influenced the experiment and influenced the outcome. a control group provides a comparison for the experiment

dangina [55]4 years ago

6 0

Answer:to see how it effects

Explanation:

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What is the half-life of a product?

Nataly [62]

The expectancy of how long a product will last divided by two!

5 0

3 years ago

A 5.5 g sample of a substance contains only carbon and oxygen. Carbon makes up 35% of the mass of the substance. The rest is mad

Umnica [9.8K]

We have been given the condition that carbon makes up 35% of the mass of the substance and the rest is made up of oxygen. With this, it can be concluded that 65% of the substance is made up of oxygen. If we let x be the mass of oxygen in the substance, the operation that would best represent the scenario is,

x = (0.65)(5.5 g)

 x = 3.575 g

8 0

3 years ago

Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2

lapo4ka [179]

Answer: Concentration of $CO$ = 0.328 M

Concentration of $Cl_2$ = 0.328 M

Concentration of $COCl_2$ = 0.532 M

Explanation:

Moles of $CO$ and $Cl_2$ = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of $CO$ and $Cl_2$ = $\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M$

The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

Concentration of $CO$ = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of $Cl_2$ = (0.860-x) M = (0.860-0.532) M = 0.328 M

Concentration of $COCl_2$ = x M = 0.532 M

3 0

3 years ago

Please help me outttt

leonid [27]

Answer:

4.) 9, 1, and 4 5.) 4, 1, and 4

Explanation:

I am not quite sure about this because I cannot remember if the coefficient (the number before the elements) is applied to every element in the compound. If it is then your number of atoms are as follows: CORRECTION: you do not have to apply the coefficient to every element only the one that is after it. So when you back and fix the error your number of atoms will be as follows:

number 4

H: 9

P: 1

O: 4

number 5:

H: 4

S: 1

O: 4

you can calculate the number of atoms present in this compound by multiplying the coefficient and the subscripts of each atom.

hope this helped you :)

7 0

3 years ago

3. A PS6 plugged into a 120 V outlet uses 3 Amps. What is the Resistance rating of

blondinia [14]

Answer:

R = 40 ohms

Explanation:

Given that,

The voltage of outlet, V = 120 V

Current flowing through the device, I = 3 A

We need to find the Resistance rating of the power cord. Let the resistance is R. We know that,

Ohm's law, V = IR

Put all the values,

$R=\dfrac{V}{I}\\\\R=\dfrac{120}{3}\\\\R=40\ \Omega$

So, the resistance rating of the power cord is equal to 40 ohms.

8 0

3 years ago

Why is it important to have a control group in an experimental investigation?​

Why is it important to have a control group in an experimental investigation?