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givi [52]
3 years ago
9

if the reactant solution is used to write on a piece of paper and the paper is allowed to partially dry, what can be done to bri

ng out the colored writing
Chemistry
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

Expose the paper to the atmosphere or moisture

Explanation:

An interesting experiment that demonstrates the equilibrium of complexes is that of the invisible ink.

The invisible ink is pink colored [Co(H2O)6]Cl2 which is essentially colorless and pale when it is used to write on paper. This complex is almost colorless when dilute. Therefore, when it is used in writing, the writing can not be seen.

However, if the paper is left to stand or allowed to absorb moisture; the following equilibrium is set up:

[Co(H2O)6]Cl2 ⇄ [CoCl2(H2O)2] + 4H2O

The formation of blue [CoCl2(H2O)2] on standing or exposure to moisture enables the colored writing to be easily read.

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Consider the following data showing the initial rate of a reaction (A→products) at several different concentrations of A.
OlgaM077 [116]

Answer:

(1) order = 2

(2) R = K [A]²

Explanation:

Given the reaction:

A--------->Product

The rate constant relation for the reaction is given as:

R(i) = K [A]............(*)

Where R(I) is rate constant at different concentration of A.

Taking the rate constant as R1, R2 and R3 for the different concentrations respectively. Then the following equations results

0.011 = K [0.15] ⁿ.........(1)

0.044 = K [0.30]ⁿ .......(2)

0.177 = K [0.60]ⁿ .........(3)

Dividing (2) by (1) and (3) by (1)

Gives:

0.044/0.011 = [0.3/0.15]ⁿ

4 = 2ⁿ; 2² = 2ⁿ; n = 2

Similarly

0.177/0.011 = [0.60/0.15]ⁿ

16.09 = 4ⁿ

16.09 = 16 (approximately)

4² = 4ⁿ ; n = 2

Hence the order of the reaction is 2.

The rate law is R = K [A]²

4 0
3 years ago
Im stuck on these two problems
Vikki [24]

1st figure

answer

c)12

2nd

answer

c)28

#brianliest

3 0
4 years ago
Fructose-2,6-bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys
azamat

Answer: Glycolysis is stimulated by a high concentration of fructose-2,6-bisphosphate, and the gluconeogenesis is stimulated by a low concentration of fructose-2,6-bisphosphate.

Explanation: Fructose-2, 6-bisphosphate (F2, 6P) is an allosteric activator of the key enzyme in the glycolysis cycle, phosphofructokinase (PFK). F2, 6P also acts as an inhibitor of fructose bisphosphate phosphatase (FBPase) in gluconeogenesis. The concentration of F2, 6P is governed by the balance between its synthesis and breakdown, catalysed by phosphofructokinase-2 (PFK-2) and fructose-bisphosphatase-2 (FBPase-2), respectively. These enzymes are found in a dimeric protein and are controlled by a phosphorylation/dephosphorylation mechanisms. Phosphorylation of the dimeric protein results in an increased concentration of FBPase-2, leading to a decreased concentration of F2, 6P, thus activating the gluconeogenesis cycle. The concentration of PFK-2 is increased when the dephosphorylation of the dimeric protein takes place, leading to the increased concentration of F2, 6P, thus stimulating glycolysis cycle.

8 0
3 years ago
Help me ASAP !!!!!!! Please give me some qestions for calculating number of moles
Leya [2.2K]
If your talking about mole. p



1 mole of water weighs 18 g

Therefore 0.5 mole of water weighs 9 g

According to Avagadro,

1 mol = 6.023 **10^23

atoms

So,

0.5 mol = 3.0115 **10^23

molecules of water

Each water molecule contains 2 hydrogen atoms .

Therefore

2** 3.00115**10^23

atoms of hydrogen are present in 9g of water

Answer:

The answer is

6.02⋅1023
3 0
3 years ago
Old thermometers contained very small amounts of mercury. The mercury in the photo has a melting point of -38.8 degrees Celsius.
Nikolay [14]

Answer:

••It's melting point equals -38.8 degrees Celsius because it is mercury. |••

Explanation:

This one makes the most sense out of the answers.

7 0
3 years ago
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