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2 years ago

1.8. Which equation is parallel to y =-3x + 4 and passes through the point (-3,4)?

Mathematics

1 answer:

STALIN [3.7K]2 years ago

4 0

Y= -3x+15 is the answer

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DedPeter [7]

Answer:

548.80

Step-by-step explanation:

$506.98 * 8.25%=

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2 years ago

Read 2 more answers

Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou

aleksklad [387]

<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>

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2 years ago

What is the product?

ZanzabumX [31]

Answer:

The product is:

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

$\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]$

$1 \times 2 + 3 \times 3 + 1 \times -2 = 15$

So the value of the element in the position $a_{11}$ is 15

$1 \times -2 + 3 \times 5 + 1 \times 1 = 14$

So the value of the element in the position $a_{12}$ is 14

Then with these two values you can determinate the result matrix.

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

3 0

2 years ago

Rewrite each expression in the form kkxxnn, where kk is a real number and nn is an integer. Assume x ≠ 0.

labwork [276]

Answer:

The expression will be $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Step-by-step explanation:

We have given the expression $2x^5\times x^{10}$

We have to write this expression in kkxxnn form , here kk is real number and nn is integer

We know the property of exponent that when two function are multiplied thn their exponent are added

So $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Here kk = 2 and nn = 15

7 0

2 years ago

Find the volume of the given solid region in the first octant bounded by the plane 9z+15y+15z=45 and the coordinate planes, usi

dem82 [27]

First,

$9x+15y+15z=45\implies 3x+5y+5z=15$

The volume is given by the integral (one of 6 possible combinations),

$\displaystyle\int_0^5\int_0^{\frac{15-3x}5}\int_0^{\frac{15-3x-5y}5}\mathrm dz\,\mathrm dy\,\mathrm dx=\boxed{\frac{15}2}$

3 0

2 years ago