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diamong [38]
3 years ago
5

Highest common factor of 24 and 40

Mathematics
2 answers:
maks197457 [2]3 years ago
5 0
24 = 2*12= 2*4*3= 2*2*2*3
40 = 5*8 = 5*2*2*2

Greatest common factor is what the number have in common as factors.
We see that both numbers have (2*2*2) = 8
So, greatest common factor is 8.
zzz [600]3 years ago
4 0
8 is the highest common factor
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Find the common ratio and the next term for the sequence shown. Express your answers as fractions or as decimals.
Cerrena [4.2K]
The common ratio of the sequence is calculated by dividing the second term by the first term or dividing the third term by the second term. That is,
                               r = 250 / 333 = 0.75
or                            r = 187 / 250 = 0.748 = 0.75
To get the next term, we multiply 187 by 0.75 giving us an answer of 140.25 or 141. 
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3 years ago
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Students in Miss Moseley's fourth grade class are learning multiplication, and they demonstrate mastery by passing assessments.
blagie [28]
<span><u><em>Answer:</em></u>
Each will have passed 17 tests and it will take 3 weeks.

<u><em>Explanation: </em></u>
Let x be the number of weeks.
The number of tests <u>Travis</u> passes to begin with is 11.
We then add 2 tests per week, or 2x to that, giving us:
11+2x.

The number of tests <u>Jenifer</u> has passed to begin with is 2.
We then add 5 tests per week, or 5x to that, giving us:
2+5x.

<u>Setting these equal, we have: </u>
11+2x=2+5x.

<u>Subtract 2x from each side: </u>
11+2x-2x=2+5x-2x;
11=2+3x.

<u>Subtract 2 from each side: </u>
11-2=2+3x-2;
9=3x.

<u>Divide both sides by 3:</u>
</span>\frac{9}{3} =  \frac{3x}{3}<span>;
3=x.

It will take <u>3 weeks</u>.
In 3 weeks,
Travis will have passed:
11+2*3 = 11+6 = 17 tests.
Jenifer will have passed the same number, since she catches up with him at this point.</span>
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3 years ago
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Please help! <br> Simplify. Your answer should contain only positive exponents.
maxonik [38]

Answer:

\frac{1}{4k^3}

Step-by-step explanation:

It's already in a form that only ha positive exponents.  Just to state it though you could rewrite it as k*(4k^{4})^{-1} or k*4^{-1}*k^{-4}  The question asks for positive exponents though so yu don't need to do that.

You also need to know \frac{x^a}{x^b}=x^{a-b} so in this case \frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}

so \frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}

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0=p-27h/17+h solve for p
shutvik [7]

Answer: The answer is p=10h/17.

Step-by-step explanation: You'll need to solve for p by simplifying the both sides of the equation, and then isolating the variable.

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