All categories

2 years ago

Find the slope from the two points given: (0, -2) and (-6, 4)

Mathematics

1 answer:

kumpel [21]2 years ago

3 0

Answer:

Step-by-step explanation:

here x1=0 y1=-2 x2=-6 y2=4

slope=y2-y1/x2-x1

=4-(-2)/-6-0

=4+2/-6

=6/-6

=-1

therefore slope=-1.

You might be interested in

Correct answers only please!

bezimeni [28]

Answer:

59%

Step-by-step explanation:

all work shown and pictured

6 0

2 years ago

Read 2 more answers

I need help with the answer

solmaris [256]

Answer:

Its the last option

y = 1488.33x + 23800 ; $172,600.

Step-by-step explanation:

The slope of the trend line = (median value for 2000 - median value for 1940) / 60

= 89300 / 60

= 1488.33.

So the equation is 1488.33x + 23,800

Estimate for 2040

is 1483.33* 100 + 23800

= 172,600.

5 0

3 years ago

Dominic is signing up for a gym membership with a one-time fee to join and then a monthly fee to remain a member. The total cost

lana [24]

The slope intercept form is y=mx+b, and b represents the y-intercept. In the given equation C=45t+100, 100 is the y-intercept. It represents the one-time fee to join the gym membership.

8 0

2 years ago

What are the solutions to the quadratic equation below?<br> 4x^2 + 28x + 49 = 5

bezimeni [28]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$