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Ymorist [56]
3 years ago
13

cheese cubes are sold in packs of 60. crackers are sold in packs of 12. to make 60 snacks of 2 cheese cubes and 1 cracker, what

is the least number of packs of each type needed?
Mathematics
2 answers:
Reil [10]3 years ago
5 0
Well, you need 2 cheese packs to get 120. and 12x5 is 60 so 5 crackers. 2 cheese 5 crackers
soldier1979 [14.2K]3 years ago
4 0
2 packs of cheese and 10 packs of crackers
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Which of the statements are true regarding dot plots bar graphs and historgrams
andrey2020 [161]

the only statement that is true is the one in option D.

"Bar graphs are used to represent data that is discrete".

<h3>Which of the statements are true regarding dot plots, bar graphs, and histograms?</h3>

Dot plots,  bar graphs, and histograms are used to repersent graphically data sets.

Thus, what these graphs do represent are populations in a data set with a given property.

Remember that data is usually discrete, so we usually use dot plots and bar graphs to represent discrete data.

Histograms show distributions of numerical data (it can be used for continuous or discrete data).

With all that in mind, we conclude that the only statement that is true is the one in option D.

"Bar graphs are used to represent data that is discrete".

If you want to learn more about data sets:

brainly.com/question/3514929

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3 0
1 year ago
If Benito is selecting samples of five values from the table, which row will result in the greatest mean? Population Data Row 1
Vilka [71]

Answer:

4th row will result in the greatest mean.

Step-by-step explanation:

We are asked to find the row with greatest mean from our given rows.

We will use formula \bar{x}=\frac{\Sigma x}{n}, where,

\bar{x}=\text{Mean},

\Sigma x=\text{Sum of all data values},

n=\text{Number of data points in sample}

Let us find mean of each row using above formula.

\text{Mean of row 1}=\frac{4+2+2+3+3}{5}

\text{Mean of row 1}=\frac{14}{5}

\text{Mean of row 1}=2.8

Therefore, mean of 1st row is 2.8.

\text{Mean of row 2}=\frac{3+3+4+3+2}{5}

\text{Mean of row 2}=\frac{15}{5}

\text{Mean of row 2}=3

Therefore, mean of 2nd row is 3.

\text{Mean of row 3}=\frac{2+4+3+4+3}{5}

\text{Mean of row 3}=\frac{16}{5}

\text{Mean of row 3}=3.2

Therefore, mean of 3rd row is 3.2.

\text{Mean of row 4}=\frac{3+4+4+7+3}{5}

\text{Mean of row 4}=\frac{21}{5}

\text{Mean of row 4}=4.2

Therefore, mean of 4th row is 4.2.

Since 4th row has the highest mean, therefore, 4th row will result in the greatest mean.

6 0
3 years ago
Read 2 more answers
solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
3 years ago
Find the area of the following shape. please show me your work so i can understand how to do this.
polet [3.4K]

Answer:

10

Step-by-step explanation:

count the full squares then add up the halfs and u get 10

4 0
3 years ago
What should be done so that the expression will have a value of 10?<br><br> 12 - 2 + 2 2 ÷ 8
Liula [17]
Answer: 10
use (PEMDAS)
P parentheses ()
E exponents
M multiplication • , () , x
D division
A addition +
S subtraction -
Explanation:
There are no parentheses.
There are exponents.
The multiplication is the exponents.
There is division.
There is addition and subtraction.
-how to solve-
First, do 2 to the second power and get 4.
Next, do 12-2+4 divided by 8.
Next do multiplication: there’s no more.
Next do division: you can’t do 4 divided by 8 so instead, do 12-2 = 10 plus 8.
Hope this helps!
3 0
2 years ago
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