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VLD [36.1K]
3 years ago
13

An architect wants to build a scale model of a building that is in the shape of a rectangular prism. The building has a height o

f 45 ft., a width of 90 ft., and a length of 300 ft. The scale model is 10% of the size of the building based off its length and width, so the length of the scale model is---- and the width of the scale model is----
Mathematics
1 answer:
julsineya [31]3 years ago
6 0

<em>Since, the area of the rectangular base = </em>

<em />

<em>We have to determine the width if length is (3x+1)</em>

<em />

<em>Let us split the middle terms of the given equation to find its factors.</em>

<em />

<em />

<em />

<em>Taking common from first, second and third, fourth terms.</em>

<em />

<em>= 3x(4x-5)+1(4x-5)</em>

<em />

<em>= (3x+1) (4x-5)</em>

<em />

<em>Since, (3x+1) is the length of the rectangular base.</em>

<em />

<em>Therefore, the width of the rectangular base is (4x-5) units.</em>

<em />

<em>Now, Volume of the rectangular prism is given by the polynomial</em>

<em />

<em />

<em />

<em>We have to find width and height.</em>

<em />

<em>Let x = -  in the given equation of volume.</em>

<em />

<em>We get as, </em>

<em />

<em>-135+135=0</em>

<em />

<em>Hence, (3x+1) is a factor of the given volume polynomial.</em>

<em />

<em>Now, performing long division of the given polynomial by (3x+1),</em>

<em />

<em>we get factors as (4x-5) and (2x-3).</em>

<em />

<em><u>So, the width is (4x-5) units and height is (2x-3) units.</u></em>

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Solve using the box method
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\huge\text{Hey there!}

\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}

\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}

\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}

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\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}

\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}

\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}

\large\text{This leaves us with }\mathsf{\bf 2x - 3}\large\text{ as your POSSIBLE  ANSWER}

\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}

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