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Verdich [7]
3 years ago
15

Suppose that a regression line for some data transformed with logarithms predicts that when x equals 6, log(y) will equal 2.012.

What does the regression line predict y will equal when x equals 6?
Mathematics
2 answers:
KIM [24]3 years ago
8 0

Answer:

102.8

Step-by-step explanation:

If log₁₀y = 2.012, y = 10^2.012 = 102.8

Mkey [24]3 years ago
8 0

Answer: The regression line predicts that at x = 6, the value of y = 102.80.

Step-by-step explanation:

Since we have given that

When x = 6,

\log y=2.012

We need to find the value of 'y' when x=6:

\log_{10}y=2.012

Since it is logarithmic function with base 10.

So, it becomes,

\log_{10}y=2.012\\\\y=10^{2.012}\\\\y=102.80

Hence, The regression line predicts that at x = 6, the value of y = 102.80.

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Help a uneducated sis out✊
N76 [4]

Answer & Step-by-step explanation:

The domain of a set of points refers to the input, also known as the x values. To find the domain, record all the x values given (x,y):

domain={-2,0,3,5}

:Done

**The range is the output, aka the y values.

5 0
2 years ago
i know this is probably simple but ive forgotten how to do it and i cant find it in my notes help appreciated!
Ronch [10]

Answer:

This is pythagoras

A squared plus b squared equals c squared.

The unknown side is c as its the hypotenuse,

So the length of the first side is 6.4 this squared = 40.96

The other length is 12 as 6 is the radius so the diameter of the circle amd therfore the length of the triangle is 12.

12 squared is 144

144 + 40.96 = 184.96

The length of c squared is 184.96

To find the length of c alone we calculate the square root.

The square root of 184.96 = 13.6

? = 13.6

8 0
2 years ago
A marble is selected from a bag, returned to the bag, and then a second marble is selected. Identify whether the events are inde
Inga [223]

Answer:

This is an independent event, as the marble is put back into the bag. If it were removed completely, it would be dependent.

6 0
3 years ago
Read 2 more answers
X - 3y = 7<br> 3x + 3y = 9<br><br><br> Please use system of elimination to answer please
yawa3891 [41]
ANSWER:

x=4 and y= -1

Explanation:

Add these equations to eliminate y:
4x=6

Then solve 4x =16 for x:
4x=16

4x/4 = 16/4 (divide both sides by 4)

x=4

Now that we have found x lets plug it back in to solve for y.
Write down an original equation:

x-3y=7

Substitute 4 for x-3y=7:

4-3y=7

-3y+4=7 (simplify both sides of the equation)

-3y+4+ (-4) = 7+ (-4) (add -4 to both sides of the equation)

-3y = 3

-3y/-3 = 3/-3 (Divide both sides by -3)

y= -1


I HOPE THIS HELPS
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B5x-3y%3D-8%7D%20%5Catop%20%7Bxy%3D12%7D%7D%20%5Cright." id="TexFormul
nignag [31]

Answer:

\left \{ {{5x-3y=-8} \atop {xy=12}} \right.\\\\\left \{ {{5x=3y-8} \atop {xy=12}} \right.\\\\\left \{ {{5x=3y-8} \atop {5xy=60}} \right.\\\\\left \{ {{5x=3y-8} \atop {(3y-8)y=60}} \right.\\\\\left \{ {{5x=3y-8} \atop {3y^{2}-8y -60=0}} \right.\\\\\left \{ {{5x=3y-8} \atop {3y^{2}-18y+10y-60 =0}} \right.\\\\\\\left \{ {{5x=3y-8} \atop {3y(y-6)+10(y-6)=0}} \right.\\\\\left \{ {{5x=3y-8} \atop {(3y+10)(y-6)=0}} \right.\\\\

<=> 5x = 3y - 8

     3y + 10 = 0 or y - 6 = 0

<=> 5x = 3y - 8

     y = -10/3 or y = 6

+) with y = -10/3 => 5x = -10 - 8 <=> 5x  = -18 <=> x = -3.6

+) with y = 6 => 5x = 3.6 - 10 = 8 <=> x = 8/5 = 1.6

Step-by-step explanation:

5 0
2 years ago
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