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nalin [4]
3 years ago
13

Chloe drives from her house to her grandma's house 64 miles away in an hour and 35 minutes. How fast was she driving on average?

About 47 mph About 53 mph About 40 mph About 30 mph
Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

<h2>She was driving at 40.42 mph on average</h2>

Step-by-step explanation:

In this exercise, for us to find the speed that Chloe drives with we need to first convert the time she spent driving to hours completely since the time given is in hours and minute

Data

distance= 64 mile

time= 1hr 35min

to covert 1 hr 35 min to hours we have

= 1 + 35/60 (we are converting 35 min to hrs)

= 1+0.583

=  1.583

hence speed= 64/ 1.583

speed= 40.42 mph

She was driving at 40.42 mph on average

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nata0808 [166]

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8 0
2 years ago
About when does the softball reach its maximum height?
Masja [62]

Based on the given graph, the time when the softball reaches its maximum height is about 1.8 seconds.

<h3>When is the softball at it highest?</h3>

The softball is at its maximum height at the point where the curve begins to go back down.

This means the maximum height is 50 feet.

The time when this softball reaches this height is between 1 and 2 seconds at 0.8.

The time the softball reaches its maximum height is therefore 1.8 seconds.

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7 0
1 year ago
Determine the currents in the picture
Elenna [48]

Answer:

The value of currents are I_1=0A, I_2=1A and I_3=1A.

Step-by-step explanation:


The Ohm's law states that

V=IR

it is given that the V₁=3V and V₂=4V.

In a parallel circuit:

  • Voltage is same in each component
  • Sum of the currents equals to the total current that flows.

I_2=I_1+I_3                   .... (1)

Equation for first loop is,

V_1=4I_1+3I_2

3=4I_1+3I_2              ..... (2)

Equation for second loop is,

V_2=1I_3+3I_2

4=1I_3+3I_2             ..... (3)

On solving (1), (2) and (3) we get

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Therefore the value of currents are I_1=0A, I_2=1A and I_3=1A.

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DiKsa [7]
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3 years ago
What is the volume of this container?
Keith_Richards [23]

Answer:

The volume of the container is 56\ in^{3}

Step-by-step explanation:

we know that

The volume of the figure is equal to

V=Bh

where

B is the area of the base

h is the height of the figure

Let

h=4\ in

Find the area of the base B

B=(4*4)-(1*2)=14\ in^{2}

substitute

V=14*4=56\ in^{3}


3 0
3 years ago
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