Simplify both sides of the equation.
<span><span><span><span>3/5</span>n </span>+ 15 </span>= <span><span><span>2/5</span>n </span>+ 10
</span></span>Subtract 2/5n from both sides.
<span><span><span><span><span>3/5</span>n </span>+ 15 - </span><span><span>2/5</span>n </span></span>= <span><span><span><span>2/5</span>n </span>+ 10 - </span><span><span>2/5</span>n</span></span></span><span><span><span><span>15</span>n </span>+ 15 </span>= 10
</span>Subtract 15 from both sides.
<span><span><span><span><span>1/5</span>n </span>+ 15 - </span>15 </span>= <span>10 - 15</span></span><span><span><span>1/5</span>n </span>= -<span>5
</span></span>Multiply both sides by 5.
<span><span>5 </span></span>× (1/5n) = (5) × (−5)<span>n = -<span><span>25
Answer: n is -25.</span></span></span>
Complete question :
Answer:
Width = 14 yards ; length = 25 yards
Step-by-step explanation:
Given that :
The length of a rectangular garden is 3 yd less than twice its length. The perimeter of the garden is 78 yd. What are the width and length of the garden?
Width of garden (W) = w
Lenght of garden (L) = 2w - 3
Perimeter of a rectangle : 2 (L + W)
2(2w - 3 + w) = 78
2(3w - 3) = 78
6w - 6 = 78
6w = 78 + 6
6w = 84
w = 14 yards
Length = 2(14) - 3
Length = 28 - 3 = 25 yards
Given:
The slope of the line is -3.
The line passes through the point (2,-2).
To find:
The point-slope form of the line.
Solution:
Point slope form: If a line passes through the point
with slope m, then the point-slope form of the line is:

The slope of the line is -3 and it passes through the point (2,-2). So, the point-slope form of the line is:


Therefore, the required point slope form of the given line is
.
If arc =AB is equal to arcCD then line AB should equa lineCD