Answer:
36
Step-by-step explanation:
Given that:
2 standard six sided dice are rolled :
Die 1 = 1, 2, 3, 4, 5, 6
Die 2 = 1, 2, 3, 4, 5, 6
Outcome = ordered pair of Number on the two dice
Event = different sum of the ordered pair of numbers.
The number of outcomes in the experiment = the sample space =) number of Faces)^number of dies
= 6^2
= 36 different outcomes
Pat attention to the ending of the numbers. If there are an odd amount of odds, it's going to be odd. If there is an even amount of odds, it's going to be even. If there's only evens, it's only going to stay even.
Answer: P(22 ≤ x ≤ 29) = 0.703
Step-by-step explanation:
Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = output of the machine in ounces per cup.
µ = mean output
σ = standard deviation
From the information given,
µ = 27
σ = 3
The probability of filling a cup between 22 and 29 ounces is expressed as
P(22 ≤ x ≤ 29)
For x = 22,
z = (22 - 27)/3 = - 1.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.047
For x = 29,
z = (29 - 27)/3 = 0.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.75
Therefore,
P(22 ≤ x ≤ 29) = 0.75 - 0.047 = 0.703
Answer:
Step-by-step explanation:
i hope it helps
You could start out by saying u put 5 groups into each number
