Question

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Answer 1

Answer:

Step-by-step explanation:

Garrett achieves a field goal is independent of each kick.  Hence X no of kicks is binomial with p = 0.83, and q =0.17

No of trials 3

Hence X can take values as 0 ,1,2,3 and

$P(X=r) = 4Cr(0.83)^r (0.17)^{4-r}$

, r=0,1,2,3

Using the above we obtain prob distribution as

X         0                  1           2            3                

P(X)   0.0049   0.0720   0.3513   0.5718

P(X>=2) =P(X=2,3,4) =0.9231

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2) Z value for company A =$\frac{260-272}{5.4} =-2.22$

Z value for company B = $(260-249)/3.8 =2.89$

From z value probablility is more for company A as

P(Z>-2.22) >P(Z>2.89)