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gladu [14]
3 years ago
11

Hey can you please help me posted picture of question

Mathematics
1 answer:
olganol [36]3 years ago
4 0
A monomial is polynomial containing one term. Consider the options:

Option A: y/x 
The polynomial cannot involve division by a variable. So this is not a  polynomial and therefore not a monomial.

Option B: Contains only 1 term. So it is a polynomial

Option C: Contains more than 1 term. So not a monomial

Option D: Contains a negative exponent. So not a polynomial and therefore not monomial.

So the correct answer is option B
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HELPPP! I’ll mark Brainliest (NO joke answers)
Licemer1 [7]

Answer: benis

jk, the answer is 3

8 0
3 years ago
Read 2 more answers
Find the 100th term for the sequence. -9,-4, 1, 6, 11, .......
Paraphin [41]

Answer:

486

Step-by-step explanation:

for the 2nd term, add 5 to -9

for the 3rd, add 5 × 2 to -9

for the 4th, add 5 × 3 to -9

:

for the 100th, add 5 × (100 - 1) to -9

=> 5 × 99 + (-9)

=> 486

8 0
3 years ago
Is (4,2) a solution of the system y=x-2 and y=3x+4
babunello [35]

Answer:

False

Step-by-step explanation:

y=x-2  y=3x+4

Substitute the point into both equations and see if it is true

2=4-2

2=2  true

and

2=3*4+4

2 = 12+4

2 =16

False

It is not a solution

4 0
3 years ago
Read 2 more answers
The burger details:
sveticcg [70]
Set up proportion  170/180=x/1  than cross multiply  170x=180 divide both sides by 170   answer 0.944  so 94% remains
6 0
3 years ago
You are testing the claim that the mean GPA of night students is different from the mea GPA of day students. You sample 20 night
svetlana [45]

Answer:

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

Step-by-step explanation:

Here n= 20

Sample mean GPA = x`= 2.84

Standard mean GPA = u= 2.55

Standard deviation = s=  0.45.

Level of Significance.= ∝ = 0.01

The hypothesis are formulated as

H0: u1=u2   i.e the GPA of night students is same as the mean GPA of day students

against the claim

Ha: u1≠u2

i.e the GPA of night students is different from the mea GPA of day students

For two tailed test  the critical value is  z ≥ z∝/2= ± 2.58

The test statistic

Z= x`-u/s/√n

z= 2.84-2.55/0.45/√20

z= 0.1441

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

8 0
3 years ago
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