Answer:
I think its P= 34/41. sorry
g(x) = the quantity of x minus one, over four
g(x) = (x-1)/4
g(5) = (5-1)/4
g(5) = 4/4
g(5) = 1
f(x) = x2 − 3x + 3
f(g(5)) =1^2 − 3(1) + 3
f(g(5)) = 1 - 3 + 3
f(g(5)) = 1
Answer:
![\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cdfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}](https://tex.z-dn.net/?f=%5Ctext%7BUse%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Cln%20a%5En%3Dn%5Cln%20a%5C%5C%5C%5C%5Cln%20e%3D1%5C%5C-----------%5C%5C%5C%5C%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cln%20e%5E%5Cfrac%7B4%7D%7B3%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cln%20e%3D%5Cdfrac%7B4%7D%7B3%7D%5Ccdot1%3D%5Cdfrac%7B4%7D%7B3%7D)
Answer:
<u>The probability that Deena will choose a pair of white socks is 4/10 or 40%</u>
Step-by-step explanation:
Let's check the information provided to us to answer the question correctly:
Total pairs or socks Deena has = 10
Pairs of white socks Deena has = 4
Pairs of black socks Deena has = 3
Pairs of red socks Deena has = 1
Pairs of navy socks Deena has = 2
If she pulls a pair of socks out of her drawer in the morning without looking, what is the probability that she will choose a pair of white socks?
Probability of Deena will choose a pair of white socks = Pairs of white socks Deena has/Total pairs or socks Deena has
Replacing with the real values, we have:
Probability of Deena will choose a pair of white socks = 4/10 or 40%
