ΔABC is right-angled at A and |AB|=2|AC|. Prove that |BC|^2=5|AC|^2

Mathematics

1 answer:

allsm [11]4 years ago

6 0

$|AB|^2+|AC|^2=|BC|^2\\\\
(2|AC|)^2+|AC|^2=5|AC|^2\\
4|AC|^2+|AC|^2=5|AC|^2\\
5|AC|^2=5|AC|^2
$

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Step-by-step explanation:

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