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OLEGan [10]
3 years ago
10

Please help me with this algebra/geometry question!

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0
There is a app called photo mathyou should use it
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In the rectangular prism shown below, which lines are parallel?
olga_2 [115]

Answer:

JN and LP...............

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Two pentagons are similar. So, their corresponding sides must have the same lengths.
Paul [167]
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Which could be the first step in solving this system of equations by substitution?
Ainat [17]

Answer:

The first step is to replace the y in y-x=15 with 7x (we can do this because the first equation tells us that they're equal)

solve and get

(2.5,17.5)

or x= 2.5 y=17.5

Step-by-step explanation:

The first step is to recognize that y=7x which means that we can just replace the y in the second equation with 7x

7x-x=15

6x=15

x=2.5

Then we can solve for y

y=7(2.5)

y=17.5

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Which situation CANNOT be represented by this equation? -1\4x + 14 = 8
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This is just a theory
6 0
3 years ago
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Rewrite the quadratic function below in Standard Form.<br> y = (x - 4) (x + 3)
Damm [24]

the standard form of a quadratic formula is

y = ax^2 + bx + c

in this case you will solve using foil method

(× - 4)(x + 3)

<em>(</em><em>x</em><em> </em><em>×</em><em> </em><em>x</em><em>)</em><em> </em><em>+</em><em>(</em><em> </em><em>x</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>)</em><em>(</em><em>-</em><em> </em><em>4</em><em> </em><em>×</em><em> </em><em>x</em><em>)</em><em> </em><em>(</em><em> </em><em>-4</em><em>)</em><em>×</em><em> </em><em>3</em><em>)</em><em>)</em>

<em>x</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>3x</em><em> </em><em>-</em><em> </em><em>4x</em><em> </em><em>-12</em>

<em>x</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em>

<em>therefore</em><em> </em>

<em>y</em><em> </em><em>=</em><em> </em><em>x^</em><em>2-</em><em> </em><em>x</em><em> </em><em><u>-</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u> </u></em>

5 0
3 years ago
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