The correct option is A.
The use of antibacterial drugs can cause modifications in the genetic material of the concerned bacteria. If the genetic material of the bacteria are modify, that means they have undergone mutation. Because the base sequence of the normal and that of the mutated gene is different, antibiotic will not be able to recognize the bacteria again and thus will not be able to attack it.
<span>The answer is A. p2 = 0.36, 2pq = 0.48, q2 = 0.16.</span>
<span>
</span><span>
Let's first distinguish alleles frequencies from
genotypes frequencies:
p - a frequency of R allele,
q - a frequency of r allele,
p² - a frequency of RR genotype,
2pq - a frequency of Rr genotype,
q² - a frequency of rr genotype.</span>
<span>
<span>The gene frequency of allele r changes from 0.38
to 0.40, thus:
q = 0.40</span>
Now, we will implement this in the following
equation:
p + q = 1
If q = 0.40, then:
p + 0.40 = 1
</span>⇒ p = 1 - 0.40<span>
</span>⇒ p = 0.60
<span>
<span>Now, the frequencies of both alleles are know
and it is easy to calculate the genotype frequencies:
- the frequency of RR genotype: p² = 0.60² = 0.36</span>
- the frequency of Rr genotype: 2pq =
2 · 0.60 · 0.40 = 0.48
- the frequency of rr genotype: q² = 0.40² =
0.16</span>
<span>
<span>Therefore, the new genotype frequencies in
that population are p2 = 0.36, 2pq = 0.48, q2 = 0.16.</span></span>
When exercising carbohydrates an fats are oxidized to release energy used by muscles, during this oxidation 1 liter of oxygen is equivalent to approximately 5 calories. Therefore if one liter of oxygen is consumed every minute during exercise, then in an hour 60 liters of oxygen will have been used. But since one liter of oxygen is equivalent to 5 calories, then in an hour 300 calories will have burned.
Answer:
A supermassive black hole is a perfectly ordinary black hole that happens to be really, really big.
