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Darya [45]
3 years ago
11

Use the graph f(x)=x^3 to graph h(x)=1/2(x-3)^2-2

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0
Can u take a picture of it
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_(9)=(2(1-2(2)^(9)))/(1-2(2))<br><br><br>PLEASE HELP ME OUT.
USPshnik [31]

Answer:

the answer = um ok

Step-by-step explanation:

4 0
3 years ago
Help me please on this please open the whole photo so you can see other problems ​
OlgaM077 [116]

Answer: 1. 57

               2. 43

              3.  20

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Step-by-step explanation: am here to help

7 0
3 years ago
(6y^2-7y-3)-(2y^2-9y-7) simplify
madreJ [45]
6y^2-7y-3-2y^2+9y+7 (pretend that you're multiplying -1 to 2y^2-9y-7 which is why 9y and 7 are positive now).
Now you're able to simplify your problem, so...

6y^2-2y^2= 4y^2
-7y+9y= 2y
-3+7=4

4y^2+2y+4

Might want to check my math but that's how you do it.
5 0
3 years ago
Do you agree? Explain why or why not.
Lelu [443]

Answer:

if x = 4

\sqrt{8 + 1} + 3 = 0

\sqrt{9} + 3 = 0

3 + 3 = 0

6 = 0

wrong.

6 0
3 years ago
Read 2 more answers
What is the equation of a vertical line passing through the point (-4, 7)?
MrRa [10]

Answer:

x=-4

Step-by-step explanation:

Since we know that the equation will be x= we will just have to take the x value of the coordinate point and that would be the x so in this case the x is -4 so the equation would be x=-4

8 0
3 years ago
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