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3 years ago

A line parallel to the line 3x+4y+8=0 with y-intercept 4

2 answers:

6 0

3x + 4y + 8 = 0
4y = -3x - 8
y = -3/4x - 2....slope here is -3/4. A parallel line will have the same slope.

y = mx + b
slope(m) = -3/4
y int (b) = 4

so ur equation is : y = -3/4x + 4

professor190 [17]3 years ago

5 0

Well you have your y so you just put y with four so it would be 3x +4 (4)+8= 0 then you multiple 4 times 4 and get 24 then you slove it like a equation

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Thepotemich [5.8K]

Step-by-step explanation:

2×2 + 8x + 26 =0

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5

Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3) = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

= 1/3 (3*(H/L)²*Q) / h² = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

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4 years ago

Demi is working on a presentation about a famous mathematician for her math class. She decides to make her poster in the shape o

sukhopar [10]

The question is incomplete. The complete question is:

Demi os working on a representation about a famous mathematician for her math class. She decides to make her poster in the shape of a plus sign. What is the total area of Demi's poster? The image and the measurements of the poster are in the attachment.

Answer: Total area = 1360 square inches

Step-by-step explanation: From the attachment, the poster is formed by two rectangles one over the other and a central part, which is a square. So, the total area is the area of the 2 rectangles minus the area of the square

A = Ar - As

As these forms are regular, the area of both is A = width * length

Area of the 2 rectangle:

width = 20 in

length = 12+20+12 = 44 in

There are 2, then:

Ar = 2.20.44

Ar = 1760

Area of the square:

width = length = 20

As = 20²

As = 400

Total Area:

At = Ar - As

At = 1760 - 400

At = 1360

The total area of the poster is 1360 square inches.

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4 years ago