QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles
![RQ/RP=RS/RT=QS/PT](https://tex.z-dn.net/?f=RQ%2FRP%3DRS%2FRT%3DQS%2FPT)
![9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm](https://tex.z-dn.net/?f=9%2FRP%3DX%2F30%3DQS%2F50%5C%5C9%2FRP%3DX%2F30%3D%2830-X%29%2F50%5C%5CX%2F30%3D%2830-X%29%2F50%5C%5C50X%3D30%2830-X%29%5C%5C50X%3D900-30X%5C%5C50X%2B30X%3D900%5C%5C80X%3D900%5C%5CX%3D900%2F80%3D11.25%5C%5CRS%3D11.25%20cm%5C%5CQS%3D30-X%3D30-11.25%5C%5CQS%3D18.75%20cm%5C%5C9%2FRP%3DX%2F30%5C%5C9%2FRP%3D11.25%2F30%5C%5C9%2A30%2F11.25%3DRP%5C%5CRP%3D24%20cm)
I think c I might be wrong tho :)
Answer:
1250%
Step-by-step explanation:
hope this helps
Here's how to figure out this problem: add up all the numbers in the mark category and divide by the # of numbers there are.
So....
6 + 7 + 8 + 9 + 10 ÷ 5 = 8
8 is your final answer.
The answer is X=3 or x=5/3