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zvonat [6]
3 years ago
5

Combine like terms to simplify -1(2/7b + 9) -8

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Simplify 2/7b to 2b/7

-1 × (2b/7 + 9) - 8

Simplify 1 × (2b/7 + 9) to (2b/7 + 9)

-(2b/7 + 9) - 8

Simplify brackets

-2b/7 - 9 - 8

Collect like terms

-2b/7 + (-9 - 8)

Simplify

<u>-2b/7 - 17</u>

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What is 15% of 135, show your work
SIZIF [17.4K]

Answer:

20.25

Step-by-step explanation:

Percentage solution with steps:

Step 1: Our output value is 135.

Step 2: We represent the unknown value with $x$

.

Step 3: From step 1 above,$135=100\%$

.

Step 4: Similarly, $x=15.\%$

.

Step 5: This results in a pair of simple equations:

$135=100\%(1)$.

$x=15.\%(2)$

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Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{135}{x}=\frac{100\%}{15.\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{135}=\frac{15.}{100}$

$\Rightarrow x=20.25$Therefore, $15.\%$ of $135$ is

sorry if it took to long have a great day and brainliest is appreciated!!!!!

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3 years ago
Which of the following notes is G?
Marta_Voda [28]
G in bass clef is the answer D!
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2 years ago
A vowel will be picked when a letter is randomly selected from the word math. HELP
Oksana_A [137]

Answer:

The answer is the letter A

5 0
3 years ago
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2 years ago
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
amm1812

Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

7 0
3 years ago
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