What is the center of a circle represented by the equation (x+9)^2+(y-6)^2=10
2 answers:
Answer:
(-9,6)
Step-by-step explanation:
Answer:
(- 9, 6)
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 9)² + (y - 6)² = 10 ← is in standard form
with (h, k) = (- 9, 6) ← coordinates of centre
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-3x+2y= -10
3x-2y=14
-3x+2y+3x-2y= -10+14
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Answer:
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Step-by-step explanation:
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