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KengaRu [80]
3 years ago
5

What is the center of a circle represented by the equation (x+9)^2+(y-6)^2=10

Mathematics
2 answers:
IRINA_888 [86]3 years ago
6 0

Answer:

(-9,6)

Step-by-step explanation:

elena55 [62]3 years ago
6 0

Answer:

(- 9, 6)

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 9)² + (y - 6)² = 10 ← is in standard form

with (h, k) = (- 9, 6) ← coordinates of centre

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A 2X2 square is centered at the origin. It is dilated by a factor of 3. What are coordinates of the vertices of the square?
Vesna [10]

Answer:

The vertices are:

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B' = (3, -3)

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D' = (-3, 3)

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

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4 years ago
What is the area of the figure?
Kipish [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

kindly find attached the solving for proper understanding and solution flow.

Given Data

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Step-by-step explanation:

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