What is the center of a circle represented by the equation (x+9)^2+(y-6)^2=10

Mathematics

2 answers:

IRINA_888 [86]2 years ago

6 0

Answer:

(-9,6)

Step-by-step explanation:

elena55 [62]2 years ago

6 0

Answer:

(- 9, 6)

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 9)² + (y - 6)² = 10 ← is in standard form

with (h, k) = (- 9, 6) ← coordinates of centre

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Given f (x) = x2 + 4x + 5, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?

meriva

By evaluating the quadratic function, we will see that the differential quotient is:

$\frac{f(2 + h) - f(2)}{h} = 8 + h$

Here we have the quadratic function:

$f(x) = x^2 + 4x + 5$

Evaluating the quadratic equation we get:

$\frac{f(2 + h) - f(2)}{h}$

So we need to replace the x-variable by "2 + h" and "2" respectively.

Replacing the function in the differential quotient:

$\frac{(2 + h)^2 + 4*(2 + h) + 5 - (2)^2 - 4*2 - 5}{h} \\\\\frac{4 + 2*2h + h^2 + 8 + 4h - 4 - 8 }{h} \\\\\frac{ 2*2h + h^2 + 4h }{h} = \frac{8h + h^2}{h}$

If we simplify that last fraction, we get:

$\frac{8h + h^2}{h} = 8 + h$

The third option is the correct one, the differential quotient is equal to 8 + 4.

If you want to learn more about quadratic functions:

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8 0

1 year ago

What is the inverse of the function g(x) = x^3/8 + 16 ?

lesya692 [45]

Answer:

$\hookrightarrow \: { \rm{f(x) = \frac{ {x}^{3} }{8} + 16}} \\$

• let f(x) be m:

${ \rm{m = \frac{ {x}^{3} }{8} + 16}} \\$

• make x the subject of the function:

${ \rm{8m = {x}^{3} + 128}} \\ \\ { \rm{ {x}^{3} = 8m - 128 }} \\ \\ { \rm{ {x}^{3} = 8(m - 16) }} \\ \\ { \rm{x = \sqrt[3]{8} \times \sqrt[3]{(m - 16)} }} \\ \\ { \rm{x = 2 \sqrt[3]{(m - 16)} }}$