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Lerok [7]
3 years ago
9

Solve for x | 2x-1| +4 = 8

Mathematics
1 answer:
Brums [2.3K]3 years ago
5 0

Answer:

x = 2 1/ 2 , − 1 1/2

Step-by-step explanation:

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14 days = 2 weeks so

14 times 3 = 42
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If (k-6)(k+2)-(k²-20)=2k+6, whatis tge value of k?​
xxMikexx [17]

K=1/3

simplify each bracket, put all numbers on the left hand side, equal it to 0 and solve for k

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Factor −13 out of −13x−8.
Citrus2011 [14]

Answer:

i believe its x+5

Step-by-step explanation:

you add 13 to both numbers

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Which expressions are equivalent to ? Check all that apply.
GrogVix [38]

Answer:

6.2+8.7+8.9x

Step-by-step explanation:

For expressions to be equivalent, they must simplify to the same lowest form. 8.9x+6.2+8.7 simplifies to 8.9x +14.9.

Each of the expressions below must simplify to 8.9x + 14.9 to be equivalent.

9x+6+9  = 9x + 15 NO

3.9+6.2+8.7x  = 8.7x + 10.1 NO

3.7+8.9+6.2  = 18.8 NO

6.2+8.7+8.9  = 23.8 NO

6.2+8.7+8.9x  = 8.9x + 14.9 YES

3.9+6.2x+8.7  = 6.2x + 12.6 NO

3.9x+8.7+6.2 = 3.9x + 14.9 NO

8 0
3 years ago
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If the rate of decrease for the partial pressure of N2H4 in a closed reaction vessel is 76 torr/h , what is the rate of change f
fiasKO [112]

The reaction is missing and it's ;

N2H4 + H2 ---> 2NH3

It asks for the total pressure too.

Answer:

A) Rate of change for NH3 = 152 torr/h

B) The total pressure in the vessel will remain the same.

Step-by-step explanation:

N2H4 + H2 ---> 2NH3

1 mole of N2H4 yields 2 moles of NH3.

From the question, the rate given for N2H4 is 76 torr/h.

Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h

Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.

While on the product side, 2 moles of NH3 are produced.

So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.

3 0
3 years ago
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