<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation
is zero
<u>Solution:</u>
For a Quadratic Equation of form :
---- eqn 1
The solution is
Now , the given Quadratic Equation is
---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In
,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.
Answer:
x-intercept(s):
(−8,0)
y-intercept(s):
(0,6)
Step-by-step explanation:
Answer:
RR = 0.4
RB = 0.3
BB = 0.22
BR = 0.30
Step-by-step explanation:
P( Urn 1 ) = 2/6 = 1/3
P( Urn 2 ) = 1 - 1/3 = 2/3
Urn 1 contains : 3 blue and 2 red
P( blue | urn 1 ) = 3/5 ( with replacement ) , P( blue | urn 1 ) = 3/4 ( without replacement )
P( red | urn 1 ) = 2 / 5 ( with replacement ) , P(red | urn 1 ) = 1/2 ( without replacement )
Urn 2 contains : 2 blue and 4 red
P ( blue | urn 2 ) = 1/3 ( with replacement ) , P( blue | urn 2 ) = 2/5 ( without replacement )
P ( red | urn 2 ) = 2/3 ( with replacement) , P( red | urn 2 ) = 4/5 ( without replacement )
Determine
<u>i) Possible outcomes when two tokens are drawn from either Urn without replacement </u>
RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4
RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3
BB = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.22
BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30
<u />
Y = -5x + 1
x = 1 , y = -4
x = 2 , y = -9
x = 3 , y = -14
so the answers are
(1,-4)
(2,-9)
(3,-14)
Answer:
x = 12
Step-by-step explanation:
In similarity triangles angles are congruent.
∠D = ∠A
x² - 8x = 48
x² - 8x - 48 = 0
x² + 4x - 12x - 48 = 0
x(x + 4) - 12(x + 4) = 0
(x +4)(x - 12) = 0
x - 12 = 0 {Ignore x + 4 = 0, as measurements won't have negative values}
x = 12