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MrRissso [65]
3 years ago
7

What's 5 times 40 plus 3 times 50

Mathematics
2 answers:
KengaRu [80]3 years ago
7 0

=200+150

=350

hope that helps!!!

lina2011 [118]3 years ago
5 0

Step-by-step explanation:

<u><em>First you had to used pemdas stands for: p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtracting that came from left to right.</em></u>

5*40+3*50

200+3*50

200+150=350

Final answer: \boxed{=350}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

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6 0
3 years ago
Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta
omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

6 0
3 years ago
a set of data has the following linear regression equation y = 1+3x what does the equation predict for a value of x=14?
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In this problem, you are simply going to input 14 for x in your equation.

y = 3x + 1
y = 3(14) + 1
y = 42+1
y = 43
This means, when x=14, y=43

Hope this helps!
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Part B:
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3 years ago
A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randoml
Andrews [41]

Answer: \dfrac{21}{410}.

Step-by-step explanation:

Formula : Probability = \dfrac{\text{favorable outcomes}}{\text{Total outcomes}}

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = \dfrac{12}{41}

Probability that the the second student obtained is a senior. =\dfrac{7}{41-1}=\dfrac{7}{40}

Then, the probability that the first student obtained is a junior and the second a senior would be \dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}

Hence, the required probability is \dfrac{21}{410}.

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