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adelina 88 [10]
3 years ago
13

Sebastian and two friends pooled their money and bought eight packages of baseball cards . there were six cards in each package.

they decided to divide the cards out evenly . how many cards will each person get
Mathematics
1 answer:
zlopas [31]3 years ago
7 0
8 • 6 = 48 cards total
48 ÷ 3 = 16 cards per person
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3(x+4)=5(x-2) I really need help i have no idea how to do it
Oksana_A [137]

<u>answer:</u>  x = 11

<u>work:</u>

3(x+4)=5(x-2)  | distribute 3 and 5 into the parentheses.

3x + 12 = 5x - 10  | subtract 5x and move it over to 3x, and solve.

-2x + 12 = -10  | subtract 12 and move it over to -10, and solve.

-2x = -22  | divide by -2.

x = 11  | final answer.

hope this helps! ❤ from peachimin

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Which fraction is represented on the number line?
Ierofanga [76]

Answer:

5/9

Step-by-step explanation:

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My ones digit is twice the hundreds digit
BlackZzzverrR [31]

The hundreds digit is twice as large as the ones digit. 3 doubled is 6, 6 doubled is 12, and 9 doubled is 18. Since 6 is the only option that is one digit, the hundreds digit must be 6 and the ones digit must be 3. The tens digit is five less than the hundreds digit.

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2 years ago
Albert O'Malley signs a promissory note for $3,500 for 150 days at 9% exact interest. Find the interest he must pay _____ and th
tia_tia [17]

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He must pay $129.45 and the total amount due is $3,629.45.

Step-by-step explanation:

I (interest) =P (principal) x R (rate) x T (time)

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I=129.45

A (amount due) = P (principal) + I (interest)

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8 0
2 years ago
When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic
Elanso [62]

Answer:

95% Confidence interval for the mean

142.8 \leq\mu\leq158.4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

cf=\sqrt{\frac{N-n}{N-1} }

The standard deviation can be estimated as

\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963

The 95% confidence interval has a z value of 1.96, so it becomes:

M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4

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3 years ago
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