Answer: No, because 4(2) + 4 ≠ 9
Step-by-step explanation:
No, because 4(2) + 4 ≠ 9
Answer:
d. 944 mm^3
Step-by-step explanation:
The area of a circle is given by ...
A = πr² . . . . . where r is the radius, half the diameter
The area of a circle with diameter 9 mm is ...
A = π(4.5 mm)² = 20.25π mm²
The area of the semi-circular end of the prism is half this value, or ...
semicircle area = (1/2)(20.25π mm²) = 10.125π mm² ≈ 31.809 mm²
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The area of the rectangular portion of the end of the prism is the product of its width and height:
A = wh = (9 mm)(6 mm) = 54 mm²
Then the base area of the prism is ...
base area = rectangle area + semicircle area
= (54 mm²) +(31.809 mm²) = 85.809 mm²
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This base area multiplied by the 11 mm length of the prism gives its volume:
V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³
The volume of the composite figure is about 944 mm³.
Silver beads = 75
gold beads = 15
75/15 = 5
5/1, or for every 1 gold bead there is, there is 5 silver beads
5 is your answer
hope this helps <em>Soto0405</em>!
Answer:
Step-by-step explanation:
Answer:
0.3 years
Step-by-step explanation:
With problems like these, I always like to start by breaking down the information into smaller pieces.
μ = 13.6
σ = 3.0
Survey of 100 self-employed people
(random variable) X = # of years of education
So now we have some notation, where μ represents population mean and σ represents population standard deviation. Hopefully, you already know that the sample mean of x-bar is the same as the population mean, so x-bar = 13.6. Now, the question asks us what the standard deviation is. Since the sample here is random, we can use the Central Limit Theorem, which allows us to guess that a distribution will be approximately normal for large sample sizes (that is, n ≥ 30). In this case, our sample size is 100, so that is satisfied. We're also told our sample is random, so we're good there, too. Now all we have to do is plug some stuff in.
The Central Limit Theorem says that for large values of n, x-bar follows an approximately normal distribution with sample mean = μ and sample standard deviation = σ/√n. So, with that info, all we need to do to find the standard deviation of x-bar is to plug our σ and n into the above formula.
σ(x-bar) = σ/√n
σ(x-bar) = 3.0/√100
σ(x-bar) = 0.3
So your answer here is .3 years.
