Step-by-step explanation:
I don't know what your teacher wants to hear here.
can you use and construct certain angles (particularly 90 degrees), can you use compasses ?
for me the best way would be to draw one side as given. then use compasses and draw a half-circle from each end point of the line above the line. both circles have the radius = the given diameter.
then draw the next 2 sides of the square up from the end points of the first line towards the half-circle that was drawn from the other point, so that the end point is exactly on the circle bow. and then connect the engaging endpoints of these 2 sides.
similar for the rectangle.
the only difference is that now for the two sides (which we don't know the length) we need to go up exactly 90 degrees until the lines hit the half-circles.
Answer:
huh try multiplying
Step-by-step explanation:
The answer is every long.
Step-by-step explanation:
as the figure shows
Answer:
Step-by-step explanation:
Depends on what you mean by multiplying by - 1. I assume you are not going to multiply the y or f(x) term by - 1.
If that is so, take an example. Suppose you have a graph that is y=x^2
That's a parabola that opens upwards and it has a line going through its focus which is a point on the +y axis.
When you multiply the right hand side by - 1, the graph you get will be y = - x^2.
That opens downward and the focus is on the - y axis.
That means that the effect of the graph is that it flips over the x axis, which I think is the third answer.
To get rid of
, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write
as a product of 2 polynomials:
From this we know, that
is the solution. Another solutions (complex roots) are the roots of quadratic equation.
