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AleksandrR [38]
3 years ago
12

Find the nonpermissible replacement for a in

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

8

Step-by-step explanation:

Assuming the given expresion is:

\frac{a + 6}{a - 8}

Then we have a rational expression with domain a≠8

This means that we can replace 'a' with all real values except a=8.

We obtain this by setting the denominator equal zero and solve for 'a'.

The reason is that, the expression is not defined when the denominator is zero.

Therefore the non-permisible replacement is 8

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Find the difference between − 1/6 and − 9/10
MrRa [10]

Answer:

Step-by-step explanation:

-1/6-(-9/10)

=-1/6+9/10

=-\frac{1}{6}+\frac{9}{10}\\=\frac{-5+27}{30}\\=\frac{22}{30}\\=\frac{11}{15}

5 0
3 years ago
Twelve of the fifty dogs in the show were some breed of terrier. What percent is this?
frozen [14]

Answer:

That would be 24%.

6 0
4 years ago
Read 2 more answers
How many solutions are there to the equation below?
UkoKoshka [18]
4x=-10
x=-5/2
C 1 solution
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3 years ago
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At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
PLEASE HELP GUYS........................................................I'M DYING WITH ALGEBRA 1..............8TH GRADE.........
Marat540 [252]
24) mari=320
jen=160

25) David= 160 Aaron=55

26)Chaya= 65 Angelica=69 Jon=62

27) 8 in one group, 16 in the other
8 0
4 years ago
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