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3 years ago

1 plus 1 I can’t figure it out bro.

Mathematics

2 answers:

jeka57 [31]3 years ago

8 0

It’s 2
Hope this helps

horrorfan [7]3 years ago

4 0

Answer: Its easy its 2.

Step-by-step explanation: If you have 1 block and you add another, you have 2 blocks. Hope this helped

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3 years ago

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3 years ago

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The teacher said estimate this with out counting 1 by 1 then divide it by 20 HELP PLEASSEE

WARRIOR [948]

Well, first fin dyour best estimate mine is...600
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3 years ago

Are these proportional?

Fudgin [204]

Answer:

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Step-by-step explanation:

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3 years ago

Plssss help quick i need it for sum important

Vanyuwa [196]

(a) The product of $(2x-4)\ and\ (3x^2-x+4)$ is calculated to be $=6x^3-14x^2+12x-16$

(b)The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

<u>Step-by-step explanation:</u>

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

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3 years ago