The formula for the number of bacteria at time t is 1000 x (2^t).
The number of bacteria after one hour is 2828
The number of minutes for there to be 50,000 bacteria is 324 minutes.
<h3>What is the number of bacteria after 1 hour?
</h3>
The exponential function that can be used to determine the number of bacteria with the passage of time is:
initial population x (rate of increase)^t
1000 x (2^t).
Population after 1 hour : 1000 x 2^(60/40) = 2828
Time when there would be 50,000 bacteria : In(FV / PV) / r
Where:
- FV = future bacteria population = 50,000
- PV = present bacteria population = 1000
- r = rate of increase = 100%
In (50,000 / 1000)
In 50 / 1 = 3.91 hours x 60 = 324 minutes
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AL=5ah!!!!!!!!!! Hope it helps
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)= 
= 
=6 weeks
V(x)= 
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, , , False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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Answer:
B!
Step-by-step explanation:
Answer:
v = 6
Step-by-step explanation:
Solve for v:
-8 (8 v + 1) - 2 = -394
-8 (8 v + 1) = -64 v - 8:
-64 v - 8 - 2 = -394
Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):
-64 v + (-8 - 2) = -394
-8 - 2 = -10:
-10 - 64 v = -394
Add 10 to both sides:
(10 - 10) - 64 v = 10 - 394
10 - 10 = 0:
-64 v = 10 - 394
10 - 394 = -384:
-64 v = -384
Divide both sides of -64 v = -384 by -64:
(-64 v)/(-64) = (-384)/(-64)
(-64)/(-64) = 1:
v = (-384)/(-64)
The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:
Answer: v = 6
