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2 years ago

Which graph represents the solution to the given system? y = –2x + 5 and y = 3x – 2

Mathematics

2 answers:

Marysya12 [62]2 years ago

7 0

For this case we have the following system of equations:
$y = -2x + 5

y = 3x - 2$
The solution of the system of equations is given by the intersection of both functions.
We have then that observing the graph the solution is given by:
$x = 7/5

y = 11/5$
Answer:
See attached image to observe the graph

DaniilM [7]2 years ago

4 0

Y = -2x + 5 y =3x - 2
Since both equations are equal to 'y' you can set them equal to each other to solve.
-2x + 5 = 3x - 2 Subtract 3x from both sides
-5x + 5 = -2 Subtract 5 from both sides
-5x = -7 Divide -5 on both sides
x = 7/5
Plug 7/5 back in for x and solve for y.
y = -2(7/5) + 5
y = (-14/5) + (25/5)
y = 11/5
(7/5, 11/5) OR (1.4, 2.2)

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If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

$\sin 2A = 2\cdot \sin A\cdot \cos A$ (4)

$\csc 2A = \frac{1}{\sin 2A}$ (5)

$f(A) = \sin 2A + \csc 2A$

$f(A) = \sin 2A + \frac{1}{\sin 2A}$

$f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}$

$f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}$

If we know that $\sin A \approx 0.382$ and $\cos A \approx 0.924$ , then the value of the function is:

$f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}$

$f(A) = 2.122$

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2 years ago

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exis [7]

Answer:

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jenyasd209 [6]

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zvonat [6]

Answer:

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Step-by-step explanation:

See the image that I have added to you above to get the whole working.

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