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goldfiish [28.3K]
4 years ago
8

If the graph of an equation has a slope of 3 and passes through the point (1, -1). What is the equation?

Mathematics
1 answer:
rusak2 [61]4 years ago
7 0

Answer: The equation has a slope of 3 and passes through the point (1,-1)

is 3 x-y=4

Step-by-step explanation:

<u>Step 1 :-</u>

An equation having slope 'm' and passing through the point

is y-y_{1} = m(x-x_{1} ).......(1)

<u>Step 2:-</u>

Now given equation slope m=3 and given point is (1,-1)

substitute these values in equation(1), we get

y-(-1)=3(x-1)

on simplification, we get

y+1 = 3 x-3

3 x-y=4

<u></u>

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5)Write the equation of a line,which is parallel to 2x -4y =12 and passing through the point (4,3) in standard form using intege
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Answer:

y=\frac{1}{2} x+1

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Parallel lines have the same slope and different y-intercepts

<u>1) Determine the slope (m)</u>

Rewrite 2x -4y =12 in slope-intercept form. This will make it easier for us to identify the slope.

Slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

2x -4y =12

Subtract 2x from both sides to isolate -4y

2x -4y-2x =-2x+ 12\\-4y=-2x+ 12

Divide both sides by -4 to isolate y

-4y=-2x+ 12\\y=\frac{1}{2}x -3

Now, we can see clearly that \frac{1}{2} is in the place of m in y=mx+b , making it the slope of the line.

Because parallel lines have the same slopes, we know that the line we're determining will also have a slope of \frac{1}{2}.

<u>2) Determine the y-intercept (b)</u>

Plug \frac{1}{2} into y=mx+b

y=\frac{1}{2} x+b

Plug in the given point (4,3)

3=\frac{1}{2} (4)+b\\3=2+b

Subtract 2 from both sides

3-2=2+b-2\\1=b

Therefore, the y-intercept (b) is 1. Plug this back into y=\frac{1}{2} x+b

y=\frac{1}{2} x+1

I hope this helps!

6 0
3 years ago
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