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Margaret [11]
3 years ago
13

How do I write y-3=2/3(x-2) in standard form

Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0
To write y-3=2/3(x-2), you must change the equation to this format: ax+by=c, whereas there are no common factors between the coefficients and constant, no fractions or decimals, and the coefficient of <em>a</em> cannot be negative. To start, first multiple both sides by 3 to get rid of the fraction 2/3. This would result in this: 3y-9=2(x-2)
Then, you distribute the 2 to (x-2) and you get 3y-9=2x-4
Now, to get this equation into ax+by=c form, subtract 2x from both sides, and add 9 to both sides, which will result in this: -2x+3y=5.
Now, since the coefficient of <em>a</em> is negative, multiply the entire equation by -1, to get you answer: 2x-3y=-5


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Okay so the y is in absolute value, which means the number could be a negative and the absolute value would make is a positive.
since the sign is greater than, with no equal to underneath it, than the answer cant be 3 or -3.
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| 4 |
| 184728 |
| -4.5829492994929492949572728 |

did that answer the problem?

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