Answer:
I am not entirely sure but I think it is 1.
Step-by-step explanation:
Don't quote me on this though. Please tell me if I am wrong.
Answer:
Step-by-step explanation:
the answer is b defenitly
Answer:
A(n) = 100(1.1)^n
Step-by-step explanation:
Given that :
Account balance = A(n)
Compound interest paid = 10%
We need to obtain the initial amount deposited, that is A(n), when n = 0
In year, n = 1
Account balance, A(n) = $110
Let initial deposit = P
Hence,
Compound interest relation should be ;
A(n) = P(1 + r)^n
Plugging in our values
110 = P(1 + 0.1)^1
110 / P = 1.1^1
110/P = 1.1
110 = 1.1P
P = 110 / 1.1
P = 100
Hence, we can define the amount paid inn n years by substuting the value of P into the compound interest formula :
A(n) = 100(1 + 0.1)^n
A(n) = 100(1.1)^n
Answer: 39$
Step-by-step explanation: calls=x x=30 30*.05= 1.50 40.50-1.50= 39$
Answer:
DG = 30
Step-by-step explanation:
Given:
DH = 6
DE = 4
EF = 16
Required:
DG
Solution:
DG = DH + HG
DG = 6 + HG
Let's find HG
Given that HE is parallel to the third side of ∆DGF, based on the side-splitter theorem, the other two sides of ∆DGF are divided proportionally.
Therefore,
DH/HG = DE/EF
6/HG = 4/16
Cross multiply
HG*4 = 16*6
HG = 96/4
HG = 24
✔️DG = 6 + HG
DG = 6 + 24
DG = 30
