I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
From left to right - (-2,6) (4,1) (-2,5) top (1,-3) bottom (-4,-1) (2,-5)
It would be 2.4 times 10. I got this answer because there is 24 shaded in, so I divided it by 10 and got 2.4. The other answers could also be 6 times 4, 8 times 3, 2 times 12, 1 times 24. I hope this helps. <3
Answer:
96
Step-by-step explanation:
Find the prime factorization of 12
12 = 2 × 2 × 3
Find the prime factorization of 32
32 = 2 × 2 × 2 × 2 × 2
Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM:
LCM = 2 × 2 × 2 × 2 × 2 × 3
LCM = 96
hope it helps ,pls mark me as brainliest
If u use scientific notion the answer for the first one would be 10^8 the second one would be 10^11 and the last one would be 10^10
Hope that Helps >.< <span />
