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anzhelika [568]
3 years ago
10

Help omg hard help please please

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0
You divide the 54 by -6, and switch the sign. Therefore the solution is n < -9
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Last question again someone pls help me I'm begging​
Norma-Jean [14]

Answer:

Go for the 200 copies!

Step-by-step explanation:

Paying 77 times $0.39 is $30.03, which is more than the 200 copies offer, so even if you throw away all the copies you don't need, the 200 offer is still cheaper!

4 0
2 years ago
Read 2 more answers
What is the Least Common Multiple (LCM) of the numbers 4 and 6?
Lady bird [3.3K]
4 : 4 8 12 16 20 24
6 : 6 12 18 24

so the LCM is 12 because 4×3 and 6×2 both give an aswer of 12
3 0
3 years ago
Which of the following is a solution to the equation y=3x - 1?
Jlenok [28]
The answers are the following
1.  B 
2. A
3. B
4. A
5 0
3 years ago
Chris has a large collection of hockey cards and wants to get of rid of some of his hockey cards. He gives 2 cards away on day 1
WINSTONCH [101]
<span>We define

day--------------------------X
hockey cards away ------------f(X)
</span><span>He gives 2 cards away ----------------on day 1----------f(X)=2   X=1
</span>He gives 4 cards away ----------------on day 2----------f(X)=4   X=2
He gives 8 cards away ----------------on day 3----------f(X)=8   X=3
the sequence of cards away      2,4,8,16,32,64,128,256,512,1024 

f(x) = 2**(x)

The answers are

D 
<span>Each day corresponds to a unique amount of hockey cards in this sequence.</span> 
And B <span>The graph of this sequence would pass the vertical line test.

Each element of the Domain (X = day), relates to a single value of f(x) = number of hockey cards

That is, every value of X must have only one corresponding value of f(x)
(One value of y, for each input X)

This can also be checked by using the vertical line test. 

If we plot f(x) and we draw vertical lines in the curve, we can verify that at every input the line intersects only one point of f(x)</span>
8 0
4 years ago
What two numbers add up to 6 and multiply to 12?
GuDViN [60]
Erm

x+y=6
xy=12


x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}
x= \frac{6+/- \sqrt{36-48} }{2}
x= \frac{6+/- \sqrt{-12} }{2}
x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}
x= \frac{6+/- (i)(2\sqrt{3}) }{2}
x= \frac{6+/- 2i\sqrt{3} }{2}
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho
7 0
4 years ago
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